Base | Representation |
---|---|
bin | 110101001111001100… |
… | …101111000100111111 |
3 | 12110112210212012101012 |
4 | 311033030233010333 |
5 | 1414032302012341 |
6 | 42132132105435 |
7 | 4062363101405 |
oct | 651714570477 |
9 | 173483765335 |
10 | 57163313471 |
11 | 22274222530 |
12 | b0b3a6527b |
13 | 550cb56654 |
14 | 2aa3c3d475 |
15 | 17486bd0eb |
hex | d4f32f13f |
57163313471 has 4 divisors (see below), whose sum is σ = 62359978344. Its totient is φ = 51966648600.
The previous prime is 57163313453. The next prime is 57163313477. The reversal of 57163313471 is 17431336175.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 57163313471 - 26 = 57163313407 is a prime.
It is a super-3 number, since 3×571633134713 (a number of 33 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (57163313477) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2598332420 + ... + 2598332441.
It is an arithmetic number, because the mean of its divisors is an integer number (15589994586).
Almost surely, 257163313471 is an apocalyptic number.
57163313471 is a deficient number, since it is larger than the sum of its proper divisors (5196664873).
57163313471 is a wasteful number, since it uses less digits than its factorization.
57163313471 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5196664872.
The product of its digits is 158760, while the sum is 41.
The spelling of 57163313471 in words is "fifty-seven billion, one hundred sixty-three million, three hundred thirteen thousand, four hundred seventy-one".
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