Base | Representation |
---|---|
bin | 110101001111010010… |
… | …110000100010001111 |
3 | 12110112220211102010110 |
4 | 311033102300202033 |
5 | 1414033203023203 |
6 | 42132230011103 |
7 | 4062412365411 |
oct | 651722604217 |
9 | 173486742113 |
10 | 57164892303 |
11 | 22275100752 |
12 | b0b44a6a93 |
13 | 551028a17c |
14 | 2aa41309b1 |
15 | 17488d0d03 |
hex | d4f4b088f |
57164892303 has 4 divisors (see below), whose sum is σ = 76219856408. Its totient is φ = 38109928200.
The previous prime is 57164892299. The next prime is 57164892311. The reversal of 57164892303 is 30329846175.
57164892303 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 57164892303 - 22 = 57164892299 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (57164892313) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9527482048 + ... + 9527482053.
It is an arithmetic number, because the mean of its divisors is an integer number (19054964102).
It is a 1-persistent number, because it is pandigital, but 2⋅57164892303 = 114329784606 is not.
Almost surely, 257164892303 is an apocalyptic number.
57164892303 is a deficient number, since it is larger than the sum of its proper divisors (19054964105).
57164892303 is a wasteful number, since it uses less digits than its factorization.
57164892303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 19054964104.
The product of its (nonzero) digits is 1088640, while the sum is 48.
The spelling of 57164892303 in words is "fifty-seven billion, one hundred sixty-four million, eight hundred ninety-two thousand, three hundred three".
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