Base | Representation |
---|---|
bin | 110101010100010111… |
… | …110101100110110001 |
3 | 12110202212011220122202 |
4 | 311110113311212301 |
5 | 1414222012003443 |
6 | 42144512312545 |
7 | 4064465622215 |
oct | 652427654661 |
9 | 173685156582 |
10 | 57250109873 |
11 | 223092159a0 |
12 | b118b42755 |
13 | 5524b26378 |
14 | 2ab1594945 |
15 | 17511157b8 |
hex | d545f59b1 |
57250109873 has 4 divisors (see below), whose sum is σ = 62454665328. Its totient is φ = 52045554420.
The previous prime is 57250109849. The next prime is 57250109923. The reversal of 57250109873 is 37890105275.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 57250109873 - 218 = 57249847729 is a prime.
It is a super-2 number, since 2×572501098732 (a number of 22 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (57250109173) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2602277711 + ... + 2602277732.
It is an arithmetic number, because the mean of its divisors is an integer number (15613666332).
Almost surely, 257250109873 is an apocalyptic number.
It is an amenable number.
57250109873 is a deficient number, since it is larger than the sum of its proper divisors (5204555455).
57250109873 is a wasteful number, since it uses less digits than its factorization.
57250109873 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5204555454.
The product of its (nonzero) digits is 529200, while the sum is 47.
The spelling of 57250109873 in words is "fifty-seven billion, two hundred fifty million, one hundred nine thousand, eight hundred seventy-three".
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