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57365741153 = 78195105879
BaseRepresentation
bin110101011011010000…
…111011111001100001
312111001220202120221202
4311123100323321201
51414441112204103
642204202530545
74100401516520
oct653320737141
9174056676852
1057365741153
1122368513436
12b14b806a55
135542a80946
142ac2a944b7
15175b356988
hexd5b43be61

57365741153 has 4 divisors (see below), whose sum is σ = 65560847040. Its totient is φ = 49170635268.

The previous prime is 57365741141. The next prime is 57365741177. The reversal of 57365741153 is 35114756375.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 57365741153 - 214 = 57365724769 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 57365741098 and 57365741107.

It is not an unprimeable number, because it can be changed into a prime (57365741353) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4097552933 + ... + 4097552946.

It is an arithmetic number, because the mean of its divisors is an integer number (16390211760).

Almost surely, 257365741153 is an apocalyptic number.

It is an amenable number.

57365741153 is a deficient number, since it is larger than the sum of its proper divisors (8195105887).

57365741153 is an equidigital number, since it uses as much as digits as its factorization.

57365741153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8195105886.

The product of its digits is 1323000, while the sum is 47.

The spelling of 57365741153 in words is "fifty-seven billion, three hundred sixty-five million, seven hundred forty-one thousand, one hundred fifty-three".

Divisors: 1 7 8195105879 57365741153