Base | Representation |
---|---|
bin | 11010000111001011110101… |
… | …00110011010010110111011 |
3 | 21112022102212022001212201111 |
4 | 31003211322212122112323 |
5 | 30011243140003420021 |
6 | 322043021123501151 |
7 | 15044364446315614 |
oct | 1503457246322673 |
9 | 245272768055644 |
10 | 57421474670011 |
11 | 173293465271a1 |
12 | 65347bb8277b7 |
13 | 2606a8b72836a |
14 | 10272ddab6c0b |
15 | 6989e71b78e1 |
hex | 34397a99a5bb |
57421474670011 has 4 divisors (see below), whose sum is σ = 60443657547400. Its totient is φ = 54399291792624.
The previous prime is 57421474669931. The next prime is 57421474670101. The reversal of 57421474670011 is 11007647412475.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 57421474670011 - 215 = 57421474637243 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (57421474670111) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1511091438666 + ... + 1511091438703.
It is an arithmetic number, because the mean of its divisors is an integer number (15110914386850).
Almost surely, 257421474670011 is an apocalyptic number.
57421474670011 is a deficient number, since it is larger than the sum of its proper divisors (3022182877389).
57421474670011 is a wasteful number, since it uses less digits than its factorization.
57421474670011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3022182877388.
The product of its (nonzero) digits is 1317120, while the sum is 49.
The spelling of 57421474670011 in words is "fifty-seven trillion, four hundred twenty-one billion, four hundred seventy-four million, six hundred seventy thousand, eleven".
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