Base | Representation |
---|---|
bin | 110101100101111001… |
… | …011100011000000111 |
3 | 12111112100102210022222 |
4 | 311211321130120013 |
5 | 1420322244211403 |
6 | 42234014242555 |
7 | 4104666023663 |
oct | 654571343007 |
9 | 174470383288 |
10 | 57544132103 |
11 | 2244a187177 |
12 | b19b4b645b |
13 | 5570a10313 |
14 | 2adc64d8a3 |
15 | 176bd43338 |
hex | d65e5c607 |
57544132103 has 8 divisors (see below), whose sum is σ = 57649128768. Its totient is φ = 57439194624.
The previous prime is 57544132067. The next prime is 57544132109. The reversal of 57544132103 is 30123144575.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 57544132103 - 26 = 57544132039 is a prime.
It is a super-2 number, since 2×575441321032 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (57544132109) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2237051 + ... + 2262627.
It is an arithmetic number, because the mean of its divisors is an integer number (7206141096).
Almost surely, 257544132103 is an apocalyptic number.
57544132103 is a deficient number, since it is larger than the sum of its proper divisors (104996665).
57544132103 is a wasteful number, since it uses less digits than its factorization.
57544132103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 29593.
The product of its (nonzero) digits is 50400, while the sum is 35.
Adding to 57544132103 its reverse (30123144575), we get a palindrome (87667276678).
The spelling of 57544132103 in words is "fifty-seven billion, five hundred forty-four million, one hundred thirty-two thousand, one hundred three".
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