Base | Representation |
---|---|
bin | 101001111000001011001… |
… | …1111011111100101110111 |
3 | 202101020021222220201211201 |
4 | 1103300112133133211313 |
5 | 1223300014141000010 |
6 | 20124033533313331 |
7 | 1132554651541606 |
oct | 123602637374567 |
9 | 22336258821751 |
10 | 5755633531255 |
11 | 1919a50096663 |
12 | 78b592035847 |
13 | 3299a546876a |
14 | 15c807673a3d |
15 | 9eab5a1823a |
hex | 53c167df977 |
5755633531255 has 16 divisors (see below), whose sum is σ = 6965936169984. Its totient is φ = 4565106120960.
The previous prime is 5755633531247. The next prime is 5755633531261. The reversal of 5755633531255 is 5521353365575.
It is not a de Polignac number, because 5755633531255 - 23 = 5755633531247 is a prime.
It is a super-3 number, since 3×57556335312553 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 5755633531196 and 5755633531205.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2196406 + ... + 4041715.
It is an arithmetic number, because the mean of its divisors is an integer number (435371010624).
Almost surely, 25755633531255 is an apocalyptic number.
5755633531255 is a deficient number, since it is larger than the sum of its proper divisors (1210302638729).
5755633531255 is a wasteful number, since it uses less digits than its factorization.
5755633531255 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6239706.
The product of its digits is 35437500, while the sum is 55.
The spelling of 5755633531255 in words is "five trillion, seven hundred fifty-five billion, six hundred thirty-three million, five hundred thirty-one thousand, two hundred fifty-five".
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