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5771430613103 = 32413178059131
BaseRepresentation
bin101001111111100010000…
…0100100101000001101111
3202102202001220220122021012
41103333010010211001233
51224024342214104403
620135205243455435
71133654300532041
oct123770404450157
922382056818235
105771430613103
111925717136001
1279266052757b
1332b32218537c
1415d4a56a3a91
15a01dc7c9ed8
hex53fc412506f

5771430613103 has 4 divisors (see below), whose sum is σ = 5771608704648. Its totient is φ = 5771252521560.

The previous prime is 5771430613049. The next prime is 5771430613129. The reversal of 5771430613103 is 3013160341775.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 5771430613103 - 214 = 5771430596719 is a prime.

It is a super-2 number, since 2×57714306131032 (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5771430613133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 88997153 + ... + 89061978.

It is an arithmetic number, because the mean of its divisors is an integer number (1442902176162).

Almost surely, 25771430613103 is an apocalyptic number.

5771430613103 is a deficient number, since it is larger than the sum of its proper divisors (178091545).

5771430613103 is a wasteful number, since it uses less digits than its factorization.

5771430613103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 178091544.

The product of its (nonzero) digits is 158760, while the sum is 41.

Adding to 5771430613103 its reverse (3013160341775), we get a palindrome (8784590954878).

The spelling of 5771430613103 in words is "five trillion, seven hundred seventy-one billion, four hundred thirty million, six hundred thirteen thousand, one hundred three".

Divisors: 1 32413 178059131 5771430613103