Base | Representation |
---|---|
bin | 101001111111100010000… |
… | …0100100101000001101111 |
3 | 202102202001220220122021012 |
4 | 1103333010010211001233 |
5 | 1224024342214104403 |
6 | 20135205243455435 |
7 | 1133654300532041 |
oct | 123770404450157 |
9 | 22382056818235 |
10 | 5771430613103 |
11 | 1925717136001 |
12 | 79266052757b |
13 | 32b32218537c |
14 | 15d4a56a3a91 |
15 | a01dc7c9ed8 |
hex | 53fc412506f |
5771430613103 has 4 divisors (see below), whose sum is σ = 5771608704648. Its totient is φ = 5771252521560.
The previous prime is 5771430613049. The next prime is 5771430613129. The reversal of 5771430613103 is 3013160341775.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 5771430613103 - 214 = 5771430596719 is a prime.
It is a super-2 number, since 2×57714306131032 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5771430613133) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 88997153 + ... + 89061978.
It is an arithmetic number, because the mean of its divisors is an integer number (1442902176162).
Almost surely, 25771430613103 is an apocalyptic number.
5771430613103 is a deficient number, since it is larger than the sum of its proper divisors (178091545).
5771430613103 is a wasteful number, since it uses less digits than its factorization.
5771430613103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 178091544.
The product of its (nonzero) digits is 158760, while the sum is 41.
Adding to 5771430613103 its reverse (3013160341775), we get a palindrome (8784590954878).
The spelling of 5771430613103 in words is "five trillion, seven hundred seventy-one billion, four hundred thirty million, six hundred thirteen thousand, one hundred three".
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