Base | Representation |
---|---|
bin | 101010000000011110111… |
… | …0001110001110111110111 |
3 | 202102221100020002111211102 |
4 | 1110000331301301313313 |
5 | 1224043032430132320 |
6 | 20140144024400315 |
7 | 1134056013402443 |
oct | 124007561616767 |
9 | 22387306074742 |
10 | 5773472505335 |
11 | 1926574795947 |
12 | 792b3031609b |
13 | 32b589209622 |
14 | 15d61a945823 |
15 | a02abbb5175 |
hex | 5403dc71df7 |
5773472505335 has 16 divisors (see below), whose sum is σ = 7311848693760. Its totient is φ = 4364259634080.
The previous prime is 5773472505301. The next prime is 5773472505347. The reversal of 5773472505335 is 5335052743775.
5773472505335 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 5773472505335 - 212 = 5773472501239 is a prime.
It is a super-4 number, since 4×57734725053354 (a number of 52 digits) contains 4444 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 79302251 + ... + 79375020.
It is an arithmetic number, because the mean of its divisors is an integer number (456990543360).
Almost surely, 25773472505335 is an apocalyptic number.
5773472505335 is a deficient number, since it is larger than the sum of its proper divisors (1538376188425).
5773472505335 is a wasteful number, since it uses less digits than its factorization.
5773472505335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 158677678.
The product of its (nonzero) digits is 46305000, while the sum is 56.
The spelling of 5773472505335 in words is "five trillion, seven hundred seventy-three billion, four hundred seventy-two million, five hundred five thousand, three hundred thirty-five".
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