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5841438113 = 7834491159
BaseRepresentation
bin1010111000010110…
…10100010110100001
3120002002200210122202
411130023110112201
543430402004423
62403350142545
7264520255550
oct53413242641
916062623582
105841438113
112528380a05
121170351a55
1372128ca74
143d5b35d97
15242c66728
hex15c2d45a1

5841438113 has 4 divisors (see below), whose sum is σ = 6675929280. Its totient is φ = 5006946948.

The previous prime is 5841438107. The next prime is 5841438199. The reversal of 5841438113 is 3118341485.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 5841438113 - 210 = 5841437089 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5841438613) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 417245573 + ... + 417245586.

It is an arithmetic number, because the mean of its divisors is an integer number (1668982320).

Almost surely, 25841438113 is an apocalyptic number.

It is an amenable number.

5841438113 is a deficient number, since it is larger than the sum of its proper divisors (834491167).

5841438113 is an equidigital number, since it uses as much as digits as its factorization.

5841438113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 834491166.

The product of its digits is 46080, while the sum is 38.

The square root of 5841438113 is about 76429.3014033231. The cubic root of 5841438113 is about 1800.9704759505.

Adding to 5841438113 its reverse (3118341485), we get a palindrome (8959779598).

The spelling of 5841438113 in words is "five billion, eight hundred forty-one million, four hundred thirty-eight thousand, one hundred thirteen".

Divisors: 1 7 834491159 5841438113