Base | Representation |
---|---|
bin | 10001001011000001000… |
… | …11000001001010101111 |
3 | 2002101222020010102202122 |
4 | 20211200203001022233 |
5 | 34131340224441421 |
6 | 1131020045143155 |
7 | 60425333621402 |
oct | 10454043011257 |
9 | 2071866112678 |
10 | 590030312111 |
11 | 208259802519 |
12 | 96427b5aabb |
13 | 438413240c6 |
14 | 207b4171d39 |
15 | 1053499b2ab |
hex | 89608c12af |
590030312111 has 4 divisors (see below), whose sum is σ = 590211361800. Its totient is φ = 589849262424.
The previous prime is 590030312057. The next prime is 590030312119. The reversal of 590030312111 is 111213030095.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 111213030095 = 5 ⋅22242606019.
It is a cyclic number.
It is not a de Polignac number, because 590030312111 - 214 = 590030295727 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (590030312119) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 90519956 + ... + 90526473.
It is an arithmetic number, because the mean of its divisors is an integer number (147552840450).
Almost surely, 2590030312111 is an apocalyptic number.
590030312111 is a deficient number, since it is larger than the sum of its proper divisors (181049689).
590030312111 is a wasteful number, since it uses less digits than its factorization.
590030312111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 181049688.
The product of its (nonzero) digits is 810, while the sum is 26.
The spelling of 590030312111 in words is "five hundred ninety billion, thirty million, three hundred twelve thousand, one hundred eleven".
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