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5995433 = 23260671
BaseRepresentation
bin10110110111101110101001
3102021121012002
4112313232221
53013323213
6332300345
7101650253
oct26675651
912247162
105995433
113425504
1220116b5
13131bbc2
14b20cd3
157d6658
hex5b7ba9

5995433 has 4 divisors (see below), whose sum is σ = 6256128. Its totient is φ = 5734740.

The previous prime is 5995427. The next prime is 5995439. The reversal of 5995433 is 3345995.

5995433 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is an interprime number because it is at equal distance from previous prime (5995427) and next prime (5995439).

It is a cyclic number.

It is not a de Polignac number, because 5995433 - 28 = 5995177 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5995439) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 130313 + ... + 130358.

It is an arithmetic number, because the mean of its divisors is an integer number (1564032).

Almost surely, 25995433 is an apocalyptic number.

It is an amenable number.

5995433 is a deficient number, since it is larger than the sum of its proper divisors (260695).

5995433 is a wasteful number, since it uses less digits than its factorization.

5995433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 260694.

The product of its digits is 72900, while the sum is 38.

The square root of 5995433 is about 2448.5573303478. The cubic root of 5995433 is about 181.6659431931.

The spelling of 5995433 in words is "five million, nine hundred ninety-five thousand, four hundred thirty-three".

Divisors: 1 23 260671 5995433