5999647063 has 4 divisors (see below), whose sum is σ = 6012605728. Its totient is φ = 5986688400.

The previous prime is 5999647039. The next prime is 5999647079. The reversal of 5999647063 is 3607469995.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-5999647063 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 5999646989 and 5999647007.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5999647013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6478638 + ... + 6479563.

It is an arithmetic number, because the mean of its divisors is an integer number (1503151432).

Almost surely, 2^5999647063 is an apocalyptic number.

5999647063 is a deficient number, since it is larger than the sum of its proper divisors (12958665).

5999647063 is a wasteful number, since it uses less digits than its factorization.

5999647063 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12958664.

The product of its (nonzero) digits is 11022480, while the sum is 58.

The square root of 5999647063 is about 77457.3886921061. The cubic root of 5999647063 is about 1817.0849627396.

The spelling of 5999647063 in words is "five billion, nine hundred ninety-nine million, six hundred forty-seven thousand, sixty-three".