60125450435701 has 4 divisors (see below), whose sum is σ = 68714800497952. Its totient is φ = 51536100373452.

The previous prime is 60125450435663. The next prime is 60125450435723. The reversal of 60125450435701 is 10753405452106.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 60125450435701 - 2¹³ = 60125450427509 is a prime.

It is a super-3 number, since 3×60125450435701³ (a number of 42 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (60125450435761) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4294675031115 + ... + 4294675031128.

It is an arithmetic number, because the mean of its divisors is an integer number (17178700124488).

Almost surely, 2^{60125450435701} is an apocalyptic number.

It is an amenable number.

60125450435701 is a deficient number, since it is larger than the sum of its proper divisors (8589350062251).

60125450435701 is an equidigital number, since it uses as much as digits as its factorization.

60125450435701 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8589350062250.

The product of its (nonzero) digits is 504000, while the sum is 43.

Adding to 60125450435701 its reverse (10753405452106), we get a palindrome (70878855887807).

The spelling of 60125450435701 in words is "sixty trillion, one hundred twenty-five billion, four hundred fifty million, four hundred thirty-five thousand, seven hundred one".