Base | Representation |
---|---|
bin | 101100000000010100100… |
… | …1011011111100001101001 |
3 | 210102011221212002122122102 |
4 | 1120000221023133201221 |
5 | 1243042303214100322 |
6 | 20510225353103145 |
7 | 1162645124563520 |
oct | 130005113374151 |
9 | 23364855078572 |
10 | 6048004831337 |
11 | 1a21a43068787 |
12 | 8181886b7ab5 |
13 | 34b42a957541 |
14 | 16ca215614b7 |
15 | a74c85c1792 |
hex | 580292df869 |
6048004831337 has 16 divisors (see below), whose sum is σ = 6987148464000. Its totient is φ = 5127830813952.
The previous prime is 6048004831291. The next prime is 6048004831339. The reversal of 6048004831337 is 7331384008406.
It is not a de Polignac number, because 6048004831337 - 234 = 6030824962153 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 6048004831291 and 6048004831300.
It is not an unprimeable number, because it can be changed into a prime (6048004831339) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 7266638 + ... + 8056055.
It is an arithmetic number, because the mean of its divisors is an integer number (436696779000).
Almost surely, 26048004831337 is an apocalyptic number.
It is an amenable number.
6048004831337 is a deficient number, since it is larger than the sum of its proper divisors (939143632663).
6048004831337 is a wasteful number, since it uses less digits than its factorization.
6048004831337 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 15323312.
The product of its (nonzero) digits is 1161216, while the sum is 47.
The spelling of 6048004831337 in words is "six trillion, forty-eight billion, four million, eight hundred thirty-one thousand, three hundred thirty-seven".
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