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61000983 = 3233120477
BaseRepresentation
bin1110100010110…
…0110100010111
311020210011121200
43220230310113
5111104012413
610015243543
71340333301
oct350546427
9136704550
1061000983
1131484a3a
12185195b3
13c83a774
14815c971
15554e573
hex3a2cd17

61000983 has 12 divisors (see below), whose sum is σ = 88383048. Its totient is φ = 40542480.

The previous prime is 61000967. The next prime is 61000997. The reversal of 61000983 is 38900016.

61000983 is nontrivially palindromic in base 2.

It is not a de Polignac number, because 61000983 - 24 = 61000967 is a prime.

It is a super-2 number, since 2×610009832 = 7442239853932578, which contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (61000943) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 7260 + ... + 13217.

It is an arithmetic number, because the mean of its divisors is an integer number (7365254).

Almost surely, 261000983 is an apocalyptic number.

61000983 is a deficient number, since it is larger than the sum of its proper divisors (27382065).

61000983 is a wasteful number, since it uses less digits than its factorization.

61000983 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 20814 (or 20811 counting only the distinct ones).

The product of its (nonzero) digits is 1296, while the sum is 27.

The square root of 61000983 is about 7810.3126057796. The cubic root of 61000983 is about 393.6518328217.

Adding to 61000983 its reverse (38900016), we get a palindrome (99900999).

The spelling of 61000983 in words is "sixty-one million, nine hundred eighty-three", and thus it is an aban number.

Divisors: 1 3 9 331 993 2979 20477 61431 184293 6777887 20333661 61000983