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61013212511303 = 134693324039331
BaseRepresentation
bin11011101111101101111101…
…10110111011110001000111
322000000210202200111001121202
431313312332312323301013
530444120024400330203
6333433025522533115
715565026166245533
oct1567667666736107
9260023680431552
1061013212511303
1118493615940328
126a1492950719b
1328076a1263950
14110d0ab826bc3
1570c161247388
hex377dbedbbc47

61013212511303 has 4 divisors (see below), whose sum is σ = 65706536550648. Its totient is φ = 56319888471960.

The previous prime is 61013212511257. The next prime is 61013212511309. The reversal of 61013212511303 is 30311521231016.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 61013212511303 - 244 = 43421026466887 is a prime.

It is a super-2 number, since 2×610132125113032 (a number of 28 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (61013212511309) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2346662019653 + ... + 2346662019678.

It is an arithmetic number, because the mean of its divisors is an integer number (16426634137662).

Almost surely, 261013212511303 is an apocalyptic number.

61013212511303 is a deficient number, since it is larger than the sum of its proper divisors (4693324039345).

61013212511303 is a wasteful number, since it uses less digits than its factorization.

61013212511303 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4693324039344.

The product of its (nonzero) digits is 3240, while the sum is 29.

Adding to 61013212511303 its reverse (30311521231016), we get a palindrome (91324733742319).

The spelling of 61013212511303 in words is "sixty-one trillion, thirteen billion, two hundred twelve million, five hundred eleven thousand, three hundred three".

Divisors: 1 13 4693324039331 61013212511303