Base | Representation |
---|---|
bin | 101100011001100111100… |
… | …1110110000101011001111 |
3 | 210121101011220002002012111 |
4 | 1120303033032300223033 |
5 | 1244440033030012143 |
6 | 20551212152444451 |
7 | 1166610301553311 |
oct | 130631716605317 |
9 | 23541156062174 |
10 | 6102330313423 |
11 | 1a42a90413513 |
12 | 82680a0a9727 |
13 | 3535a7899206 |
14 | 1714d652d7b1 |
15 | a8b07a8099d |
hex | 58ccf3b0acf |
6102330313423 has 4 divisors (see below), whose sum is σ = 6102372722688. Its totient is φ = 6102287904160.
The previous prime is 6102330313421. The next prime is 6102330313489. The reversal of 6102330313423 is 3243130332016.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 6102330313423 - 21 = 6102330313421 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (6102330313421) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20988058 + ... + 21276823.
It is an arithmetic number, because the mean of its divisors is an integer number (1525593180672).
Almost surely, 26102330313423 is an apocalyptic number.
6102330313423 is a deficient number, since it is larger than the sum of its proper divisors (42409265).
6102330313423 is a wasteful number, since it uses less digits than its factorization.
6102330313423 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 42409264.
The product of its (nonzero) digits is 23328, while the sum is 31.
Adding to 6102330313423 its reverse (3243130332016), we get a palindrome (9345460645439).
The spelling of 6102330313423 in words is "six trillion, one hundred two billion, three hundred thirty million, three hundred thirteen thousand, four hundred twenty-three".
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