Base | Representation |
---|---|
bin | 11011110000100100001100… |
… | …00111011011010001110001 |
3 | 22000010120220121100011222011 |
4 | 31320102012013123101301 |
5 | 31000104140234220213 |
6 | 333454242423042521 |
7 | 15600106504020454 |
oct | 1570220607332161 |
9 | 260116817304864 |
10 | 61042325304433 |
11 | 184a49a529a740 |
12 | 6a1a4b32a0441 |
13 | 280a360891365 |
14 | 11106700c549b |
15 | 70ccb702003d |
hex | 3784861db471 |
61042325304433 has 32 divisors (see below), whose sum is σ = 70025994547200. Its totient is φ = 52670067542400.
The previous prime is 61042325304397. The next prime is 61042325304437. The reversal of 61042325304433 is 33440352324016.
It is not a de Polignac number, because 61042325304433 - 213 = 61042325296241 is a prime.
It is a super-2 number, since 2×610423253044332 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (61042325304437) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 15194938 + ... + 18787516.
It is an arithmetic number, because the mean of its divisors is an integer number (2188312329600).
Almost surely, 261042325304433 is an apocalyptic number.
It is an amenable number.
61042325304433 is a deficient number, since it is larger than the sum of its proper divisors (8983669242767).
61042325304433 is a wasteful number, since it uses less digits than its factorization.
61042325304433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3593133.
The product of its (nonzero) digits is 622080, while the sum is 40.
Adding to 61042325304433 its reverse (33440352324016), we get a palindrome (94482677628449).
The spelling of 61042325304433 in words is "sixty-one trillion, forty-two billion, three hundred twenty-five million, three hundred four thousand, four hundred thirty-three".
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