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6113102326113 = 32037700775371
BaseRepresentation
bin101100011110101000101…
…0010101110100101100001
3210122101222121112000122110
41120331101102232211201
51300124113143413423
621000153114225533
71200441242265156
oct130752122564541
923571877460573
106113102326113
111a47608993042
128289157252a9
133546034ba713
14171c3901422d
15a90385d8193
hex58f514ae961

6113102326113 has 4 divisors (see below), whose sum is σ = 8150803101488. Its totient is φ = 4075401550740.

The previous prime is 6113102326103. The next prime is 6113102326117. The reversal of 6113102326113 is 3116232013116.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 6113102326113 - 25 = 6113102326081 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (6113102326117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1018850387683 + ... + 1018850387688.

It is an arithmetic number, because the mean of its divisors is an integer number (2037700775372).

Almost surely, 26113102326113 is an apocalyptic number.

It is an amenable number.

6113102326113 is a deficient number, since it is larger than the sum of its proper divisors (2037700775375).

6113102326113 is a wasteful number, since it uses less digits than its factorization.

6113102326113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2037700775374.

The product of its (nonzero) digits is 3888, while the sum is 30.

Adding to 6113102326113 its reverse (3116232013116), we get a palindrome (9229334339229).

The spelling of 6113102326113 in words is "six trillion, one hundred thirteen billion, one hundred two million, three hundred twenty-six thousand, one hundred thirteen".

Divisors: 1 3 2037700775371 6113102326113