Base | Representation |
---|---|
bin | 101100011110101001001… |
… | …0110100111100100010101 |
3 | 210122102000212000012121020 |
4 | 1120331102112213210111 |
5 | 1300124132222420112 |
6 | 21000154551511353 |
7 | 1200441546460455 |
oct | 130752226474425 |
9 | 23572025005536 |
10 | 6113120123157 |
11 | 1a47617a39243 |
12 | 82891b688559 |
13 | 3546070ac208 |
14 | 171c3b527d65 |
15 | a9039e5148c |
hex | 58f525a7915 |
6113120123157 has 4 divisors (see below), whose sum is σ = 8150826830880. Its totient is φ = 4075413415436.
The previous prime is 6113120123147. The next prime is 6113120123219. The reversal of 6113120123157 is 7513210213116.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 6113120123157 - 24 = 6113120123141 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (6113120123147) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1018853353857 + ... + 1018853353862.
It is an arithmetic number, because the mean of its divisors is an integer number (2037706707720).
Almost surely, 26113120123157 is an apocalyptic number.
It is an amenable number.
6113120123157 is a deficient number, since it is larger than the sum of its proper divisors (2037706707723).
6113120123157 is a wasteful number, since it uses less digits than its factorization.
6113120123157 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2037706707722.
The product of its (nonzero) digits is 7560, while the sum is 33.
The spelling of 6113120123157 in words is "six trillion, one hundred thirteen billion, one hundred twenty million, one hundred twenty-three thousand, one hundred fifty-seven".
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