Base | Representation |
---|---|
bin | 10001110010110100101… |
… | …01001000011100101111 |
3 | 2011110010120112222211120 |
4 | 20321122111020130233 |
5 | 40004122104020403 |
6 | 1144512413552023 |
7 | 62113040302326 |
oct | 10713225103457 |
9 | 2143116488746 |
10 | 611400845103 |
11 | 216325924234 |
12 | 9a5b0aa5613 |
13 | 45868930cb9 |
14 | 218404990bd |
15 | 10d85bdae53 |
hex | 8e5a54872f |
611400845103 has 8 divisors (see below), whose sum is σ = 815207564928. Its totient is φ = 407597344344.
The previous prime is 611400845089. The next prime is 611400845213. The reversal of 611400845103 is 301548004116.
611400845103 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 611400845103 - 221 = 611398747951 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (611400843103) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 319851 + ... + 1151132.
It is an arithmetic number, because the mean of its divisors is an integer number (101900945616).
Almost surely, 2611400845103 is an apocalyptic number.
611400845103 is a deficient number, since it is larger than the sum of its proper divisors (203806719825).
611400845103 is a wasteful number, since it uses less digits than its factorization.
611400845103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1609533.
The product of its (nonzero) digits is 11520, while the sum is 33.
Adding to 611400845103 its reverse (301548004116), we get a palindrome (912948849219).
The spelling of 611400845103 in words is "six hundred eleven billion, four hundred million, eight hundred forty-five thousand, one hundred three".
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