Base | Representation |
---|---|
bin | 10001110010110100110… |
… | …10000101110101011001 |
3 | 2011110010200000001010002 |
4 | 20321122122011311121 |
5 | 40004122422120423 |
6 | 1144512501502345 |
7 | 62113054325414 |
oct | 10713232056531 |
9 | 2143120001102 |
10 | 611402145113 |
11 | 216326631a21 |
12 | 9a5b14119b5 |
13 | 45868c97936 |
14 | 21840716b7b |
15 | 10d85d96228 |
hex | 8e5a685d59 |
611402145113 has 16 divisors (see below), whose sum is σ = 631477002240. Its totient is φ = 591653918016.
The previous prime is 611402145089. The next prime is 611402145119. The reversal of 611402145113 is 311541204116.
611402145113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 611402145113 - 212 = 611402141017 is a prime.
It is a super-3 number, since 3×6114021451133 (a number of 36 digits) contains 333 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (611402145119) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1574123 + ... + 1923711.
It is an arithmetic number, because the mean of its divisors is an integer number (39467312640).
Almost surely, 2611402145113 is an apocalyptic number.
It is an amenable number.
611402145113 is a deficient number, since it is larger than the sum of its proper divisors (20074857127).
611402145113 is a wasteful number, since it uses less digits than its factorization.
611402145113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 350056.
The product of its (nonzero) digits is 2880, while the sum is 29.
Adding to 611402145113 its reverse (311541204116), we get a palindrome (922943349229).
The spelling of 611402145113 in words is "six hundred eleven billion, four hundred two million, one hundred forty-five thousand, one hundred thirteen".
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