Base | Representation |
---|---|
bin | 1000101100111111001001010… |
… | …1110011100000101000010111 |
3 | 2222022101010210112212022020002 |
4 | 2023033302111303200220113 |
5 | 1120232234424342011411 |
6 | 10010254442444401515 |
7 | 242665254505246610 |
oct | 21317622563405027 |
9 | 2868333715768202 |
10 | 612413310110231 |
11 | 168152031a7aa43 |
12 | 5882997654629b |
13 | 203944342370c6 |
14 | ab32d68a20c07 |
15 | 4ac042029333b |
hex | 22cfc95ce0a17 |
612413310110231 has 8 divisors (see below), whose sum is σ = 701747630133120. Its totient is φ = 523540666160568.
The previous prime is 612413310110227. The next prime is 612413310110243. The reversal of 612413310110231 is 132011013314216.
612413310110231 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 612413310110231 - 22 = 612413310110227 is a prime.
It is a super-2 number, since 2×6124133101102312 (a number of 30 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 612413310110194 and 612413310110203.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (612413310110281) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 115419015461 + ... + 115419020766.
It is an arithmetic number, because the mean of its divisors is an integer number (87718453766640).
Almost surely, 2612413310110231 is an apocalyptic number.
612413310110231 is a deficient number, since it is larger than the sum of its proper divisors (89334320022889).
612413310110231 is a wasteful number, since it uses less digits than its factorization.
612413310110231 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 230838036613.
The product of its (nonzero) digits is 2592, while the sum is 29.
Adding to 612413310110231 its reverse (132011013314216), we get a palindrome (744424323424447).
The spelling of 612413310110231 in words is "six hundred twelve trillion, four hundred thirteen billion, three hundred ten million, one hundred ten thousand, two hundred thirty-one".
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