Base | Representation |
---|---|
bin | 10001110110001110001… |
… | …00100111111000010111 |
3 | 2011121211201110112211121 |
4 | 20323013010213320113 |
5 | 40021341124441233 |
6 | 1145413424544411 |
7 | 62206202325250 |
oct | 10730704477027 |
9 | 2147751415747 |
10 | 613225233943 |
11 | 217081726603 |
12 | 9aa1ba82107 |
13 | 45a998b001a |
14 | 219748bdb27 |
15 | 10e40e6092d |
hex | 8ec7127e17 |
613225233943 has 16 divisors (see below), whose sum is σ = 718631274816. Its totient is φ = 512295125760.
The previous prime is 613225233937. The next prime is 613225234019. The reversal of 613225233943 is 349332522316.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-613225233943 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 613225233943.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (613225233913) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 763896 + ... + 1345357.
It is an arithmetic number, because the mean of its divisors is an integer number (44914454676).
Almost surely, 2613225233943 is an apocalyptic number.
613225233943 is a deficient number, since it is larger than the sum of its proper divisors (105406040873).
613225233943 is a wasteful number, since it uses less digits than its factorization.
613225233943 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2110314.
The product of its digits is 699840, while the sum is 43.
The spelling of 613225233943 in words is "six hundred thirteen billion, two hundred twenty-five million, two hundred thirty-three thousand, nine hundred forty-three".
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