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6138336108347 = 6791616956841
BaseRepresentation
bin101100101010011000101…
…0101111101111100111011
3210201211010012022222101122
41121110301111331330323
51301032303020431342
621015525045535455
71202323456014332
oct131246125757473
923654105288348
106138336108347
111a57287786123
1283179841458b
13356ac52a8901
14173150454d19
15a9a13a894d2
hex5953157df3b

6138336108347 has 4 divisors (see below), whose sum is σ = 6229953065256. Its totient is φ = 6046719151440.

The previous prime is 6138336108257. The next prime is 6138336108349. The reversal of 6138336108347 is 7438016338316.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 6138336108347 - 214 = 6138336091963 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (6138336108349) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 45808478354 + ... + 45808478487.

It is an arithmetic number, because the mean of its divisors is an integer number (1557488266314).

Almost surely, 26138336108347 is an apocalyptic number.

6138336108347 is a gapful number since it is divisible by the number (67) formed by its first and last digit.

6138336108347 is a deficient number, since it is larger than the sum of its proper divisors (91616956909).

6138336108347 is an equidigital number, since it uses as much as digits as its factorization.

6138336108347 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 91616956908.

The product of its (nonzero) digits is 5225472, while the sum is 53.

The spelling of 6138336108347 in words is "six trillion, one hundred thirty-eight billion, three hundred thirty-six million, one hundred eight thousand, three hundred forty-seven".

Divisors: 1 67 91616956841 6138336108347