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61412433 = 320470811
BaseRepresentation
bin1110101001000…
…1010001010001
311021120002000120
43222101101101
5111210144213
610032140453
71343665665
oct352212121
9137502016
1061412433
1131736085
1218697729
13c952b24
1482288a5
1555d1423
hex3a91451

61412433 has 4 divisors (see below), whose sum is σ = 81883248. Its totient is φ = 40941620.

The previous prime is 61412419. The next prime is 61412437. The reversal of 61412433 is 33421416.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 61412433 - 210 = 61411409 is a prime.

It is not an unprimeable number, because it can be changed into a prime (61412437) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10235403 + ... + 10235408.

It is an arithmetic number, because the mean of its divisors is an integer number (20470812).

Almost surely, 261412433 is an apocalyptic number.

It is an amenable number.

61412433 is a deficient number, since it is larger than the sum of its proper divisors (20470815).

61412433 is a wasteful number, since it uses less digits than its factorization.

61412433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 20470814.

The product of its digits is 1728, while the sum is 24.

The square root of 61412433 is about 7836.6085138917. The cubic root of 61412433 is about 394.5349073800.

Adding to 61412433 its reverse (33421416), we get a palindrome (94833849).

The spelling of 61412433 in words is "sixty-one million, four hundred twelve thousand, four hundred thirty-three".

Divisors: 1 3 20470811 61412433