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6142004441351 = 17361294378903
BaseRepresentation
bin101100101100000101111…
…1111100011000100000111
3210202011120211221121020222
41121120023333203010013
51301112311114110401
621021333051014555
71202513411230622
oct131301377430407
923664524847228
106142004441351
111a5889a426a99
12832440a3a45b
1335725b29285c
141733bb710db9
15a9b7ab47c1b
hex5960bfe3107

6142004441351 has 4 divisors (see below), whose sum is σ = 6503298820272. Its totient is φ = 5780710062432.

The previous prime is 6142004441231. The next prime is 6142004441381. The reversal of 6142004441351 is 1531444002416.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-6142004441351 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (6142004441381) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 180647189435 + ... + 180647189468.

It is an arithmetic number, because the mean of its divisors is an integer number (1625824705068).

Almost surely, 26142004441351 is an apocalyptic number.

6142004441351 is a deficient number, since it is larger than the sum of its proper divisors (361294378921).

6142004441351 is a wasteful number, since it uses less digits than its factorization.

6142004441351 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 361294378920.

The product of its (nonzero) digits is 46080, while the sum is 35.

Adding to 6142004441351 its reverse (1531444002416), we get a palindrome (7673448443767).

The spelling of 6142004441351 in words is "six trillion, one hundred forty-two billion, four million, four hundred forty-one thousand, three hundred fifty-one".

Divisors: 1 17 361294378903 6142004441351