Base | Representation |
---|---|
bin | 10001111000000110011… |
… | …00111100111000000011 |
3 | 2011201110000201201101011 |
4 | 20330003030330320003 |
5 | 40030422404100201 |
6 | 1150101503221351 |
7 | 62243202165136 |
oct | 10740314747003 |
9 | 2151400651334 |
10 | 614234050051 |
11 | 21754a121026 |
12 | 9b0618a7857 |
13 | 45bca8b5c2b |
14 | 21a2c88421d |
15 | 10e9e7d4151 |
hex | 8f0333ce03 |
614234050051 has 4 divisors (see below), whose sum is σ = 614236055832. Its totient is φ = 614232044272.
The previous prime is 614234050033. The next prime is 614234050061. The reversal of 614234050051 is 150050432416.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 614234050051 - 217 = 614233918979 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 614234049995 and 614234050022.
It is not an unprimeable number, because it can be changed into a prime (614234050061) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 437170 + ... + 1191463.
It is an arithmetic number, because the mean of its divisors is an integer number (153559013958).
Almost surely, 2614234050051 is an apocalyptic number.
614234050051 is a deficient number, since it is larger than the sum of its proper divisors (2005781).
614234050051 is a wasteful number, since it uses less digits than its factorization.
614234050051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2005780.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 614234050051 its reverse (150050432416), we get a palindrome (764284482467).
The spelling of 614234050051 in words is "six hundred fourteen billion, two hundred thirty-four million, fifty thousand, fifty-one".
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