Base | Representation |
---|---|
bin | 111001010001001001… |
… | …010111110111010011 |
3 | 12212201102002002201000 |
4 | 321101021113313103 |
5 | 2001413141004213 |
6 | 44125404313043 |
7 | 4304542324305 |
oct | 712111276723 |
9 | 185642062630 |
10 | 61490953683 |
11 | 24095049695 |
12 | bb01242783 |
13 | 5a4c6029c3 |
14 | 2d948bd975 |
15 | 18ed5b1c73 |
hex | e51257dd3 |
61490953683 has 16 divisors (see below), whose sum is σ = 91793116800. Its totient is φ = 40681035720.
The previous prime is 61490953631. The next prime is 61490953687. The reversal of 61490953683 is 38635909416.
61490953683 is a `hidden beast` number, since 6 + 1 + 490 + 95 + 3 + 68 + 3 = 666.
It is not a de Polignac number, because 61490953683 - 28 = 61490953427 is a prime.
It is a super-2 number, since 2×614909536832 (a number of 22 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (61490953687) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 8688993 + ... + 8696066.
It is an arithmetic number, because the mean of its divisors is an integer number (5737069800).
Almost surely, 261490953683 is an apocalyptic number.
61490953683 is a deficient number, since it is larger than the sum of its proper divisors (30302163117).
61490953683 is a wasteful number, since it uses less digits than its factorization.
61490953683 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 17385199 (or 17385193 counting only the distinct ones).
The product of its (nonzero) digits is 4199040, while the sum is 54.
The spelling of 61490953683 in words is "sixty-one billion, four hundred ninety million, nine hundred fifty-three thousand, six hundred eighty-three".
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