Base | Representation |
---|---|
bin | 11011111110011110010000… |
… | …00010000101010110011101 |
3 | 22001211021022121021101111111 |
4 | 31333033020002011112131 |
5 | 31030421303134220023 |
6 | 334501551020222021 |
7 | 15646454140532443 |
oct | 1577171002052635 |
9 | 261737277241444 |
10 | 61520172570013 |
11 | 18669616651963 |
12 | 6a9703139a911 |
13 | 2843434341751 |
14 | 112984116ab93 |
15 | 71a432e0500d |
hex | 37f3c808559d |
61520172570013 has 16 divisors (see below), whose sum is σ = 66063216384000. Its totient is φ = 57079985670400.
The previous prime is 61520172569897. The next prime is 61520172570019. The reversal of 61520172570013 is 31007527102516.
It is a cyclic number.
It is not a de Polignac number, because 61520172570013 - 29 = 61520172569501 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (61520172570019) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 9214863 + ... + 14420611.
It is an arithmetic number, because the mean of its divisors is an integer number (4128951024000).
Almost surely, 261520172570013 is an apocalyptic number.
It is an amenable number.
61520172570013 is a deficient number, since it is larger than the sum of its proper divisors (4543043813987).
61520172570013 is a wasteful number, since it uses less digits than its factorization.
61520172570013 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5215628.
The product of its (nonzero) digits is 88200, while the sum is 40.
Adding to 61520172570013 its reverse (31007527102516), we get a palindrome (92527699672529).
The spelling of 61520172570013 in words is "sixty-one trillion, five hundred twenty billion, one hundred seventy-two million, five hundred seventy thousand, thirteen".
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