Base | Representation |
---|---|
bin | 111001010011011111… |
… | …100001000100101001 |
3 | 12212211011010202112112 |
4 | 321103133201010221 |
5 | 2002003230004001 |
6 | 44133332052105 |
7 | 4305531013433 |
oct | 712337410451 |
9 | 185734122475 |
10 | 61530313001 |
11 | 24105291953 |
12 | bb12464035 |
13 | 5a57803a41 |
14 | 2d99c07653 |
15 | 1901c88cbb |
hex | e537e1129 |
61530313001 has 4 divisors (see below), whose sum is σ = 61532103504. Its totient is φ = 61528522500.
The previous prime is 61530312997. The next prime is 61530313003. The reversal of 61530313001 is 10031303516.
It is a happy number.
61530313001 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 61530313001 - 22 = 61530312997 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (61530313003) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 842675 + ... + 912776.
It is an arithmetic number, because the mean of its divisors is an integer number (15383025876).
Almost surely, 261530313001 is an apocalyptic number.
It is an amenable number.
61530313001 is a deficient number, since it is larger than the sum of its proper divisors (1790503).
61530313001 is a wasteful number, since it uses less digits than its factorization.
61530313001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1790502.
The product of its (nonzero) digits is 810, while the sum is 23.
Adding to 61530313001 its reverse (10031303516), we get a palindrome (71561616517).
The spelling of 61530313001 in words is "sixty-one billion, five hundred thirty million, three hundred thirteen thousand, one".
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