Base | Representation |
---|---|
bin | 111001011101011101… |
… | …011111100000000001 |
3 | 12220020210211111122122 |
4 | 321131131133200001 |
5 | 2002324033220213 |
6 | 44202104414025 |
7 | 4312631362664 |
oct | 713535374001 |
9 | 186223744578 |
10 | 61697554433 |
11 | 2419072a909 |
12 | bb5a477315 |
13 | 5a8335b578 |
14 | 2db40dd6db |
15 | 19117c1d08 |
hex | e5d75f801 |
61697554433 has 12 divisors (see below), whose sum is σ = 67361081940. Its totient is φ = 56434777056.
The previous prime is 61697554367. The next prime is 61697554469. The reversal of 61697554433 is 33445579616.
It can be written as a sum of positive squares in 2 ways, for example, as 10033628224 + 51663926209 = 100168^2 + 227297^2 .
It is not a de Polignac number, because 61697554433 - 218 = 61697292289 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (61697554133) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 2936210 + ... + 2957147.
It is an arithmetic number, because the mean of its divisors is an integer number (5613423495).
Almost surely, 261697554433 is an apocalyptic number.
It is an amenable number.
61697554433 is a deficient number, since it is larger than the sum of its proper divisors (5663527507).
61697554433 is a wasteful number, since it uses less digits than its factorization.
61697554433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5893424 (or 5893405 counting only the distinct ones).
The product of its digits is 8164800, while the sum is 53.
The spelling of 61697554433 in words is "sixty-one billion, six hundred ninety-seven million, five hundred fifty-four thousand, four hundred thirty-three".
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