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61983943 = 78854849
BaseRepresentation
bin1110110001110…
…0110011000111
311022122002222121
43230130303013
5111331441233
610052310411
71351566130
oct354346307
9138562877
1061983943
1131a964aa
1218912407
13cac2cb8
148336c87
15569592d
hex3b1ccc7

61983943 has 4 divisors (see below), whose sum is σ = 70838800. Its totient is φ = 53129088.

The previous prime is 61983937. The next prime is 61983959. The reversal of 61983943 is 34938916.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-61983943 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 61983943.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (61983913) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4427418 + ... + 4427431.

It is an arithmetic number, because the mean of its divisors is an integer number (17709700).

Almost surely, 261983943 is an apocalyptic number.

61983943 is a deficient number, since it is larger than the sum of its proper divisors (8854857).

61983943 is an equidigital number, since it uses as much as digits as its factorization.

61983943 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8854856.

The product of its digits is 139968, while the sum is 43.

The square root of 61983943 is about 7872.9881874673. The cubic root of 61983943 is about 395.7549903483.

It can be divided in two parts, 61983 and 943, that added together give a palindrome (62926).

The spelling of 61983943 in words is "sixty-one million, nine hundred eighty-three thousand, nine hundred forty-three".

Divisors: 1 7 8854849 61983943