Base | Representation |
---|---|
bin | 101101011010110100101… |
… | …0100000010000100011111 |
3 | 211002202121101222122101121 |
4 | 1122311221110002010133 |
5 | 1304233320202341002 |
6 | 21135410433351411 |
7 | 1212665234262313 |
oct | 132655124020437 |
9 | 24082541878347 |
10 | 6242354340127 |
11 | 1a97405318234 |
12 | 849987a08567 |
13 | 363861421399 |
14 | 1781bb013b43 |
15 | ac5a094b237 |
hex | 5ad6950211f |
6242354340127 has 4 divisors (see below), whose sum is σ = 6344688017896. Its totient is φ = 6140020662360.
The previous prime is 6242354340113. The next prime is 6242354340151. The reversal of 6242354340127 is 7210434532426.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-6242354340127 is a prime.
It is a super-2 number, since 2×62423543401272 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (6242354340107) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 51166838793 + ... + 51166838914.
It is an arithmetic number, because the mean of its divisors is an integer number (1586172004474).
Almost surely, 26242354340127 is an apocalyptic number.
6242354340127 is a deficient number, since it is larger than the sum of its proper divisors (102333677769).
6242354340127 is a wasteful number, since it uses less digits than its factorization.
6242354340127 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 102333677768.
The product of its (nonzero) digits is 967680, while the sum is 43.
The spelling of 6242354340127 in words is "six trillion, two hundred forty-two billion, three hundred fifty-four million, three hundred forty thousand, one hundred twenty-seven".
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