Base | Representation |
---|---|
bin | 11100101101101001011110… |
… | …10111001000100110101001 |
3 | 22021120020020102210011120002 |
4 | 32112310233113020212221 |
5 | 31234000442323442301 |
6 | 342142342553312345 |
7 | 16204536352336460 |
oct | 1626645727104651 |
9 | 267506212704502 |
10 | 63141108812201 |
11 | 19133aa2925a42 |
12 | 70b92057056b5 |
13 | 29302478b8074 |
14 | 11840902119d7 |
15 | 7476a254016b |
hex | 396d2f5c89a9 |
63141108812201 has 4 divisors (see below), whose sum is σ = 72161267213952. Its totient is φ = 54120950410452.
The previous prime is 63141108812147. The next prime is 63141108812203. The reversal of 63141108812201 is 10221880114136.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 63141108812201 - 230 = 63140035070377 is a prime.
It is not an unprimeable number, because it can be changed into a prime (63141108812203) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4510079200865 + ... + 4510079200878.
It is an arithmetic number, because the mean of its divisors is an integer number (18040316803488).
Almost surely, 263141108812201 is an apocalyptic number.
It is an amenable number.
63141108812201 is a deficient number, since it is larger than the sum of its proper divisors (9020158401751).
63141108812201 is an equidigital number, since it uses as much as digits as its factorization.
63141108812201 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 9020158401750.
The product of its (nonzero) digits is 18432, while the sum is 38.
Adding to 63141108812201 its reverse (10221880114136), we get a palindrome (73362988926337).
The spelling of 63141108812201 in words is "sixty-three trillion, one hundred forty-one billion, one hundred eight million, eight hundred twelve thousand, two hundred one".
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