Base | Representation |
---|---|
bin | 111010110011101001… |
… | …001010100100011001 |
3 | 20000222120112212100112 |
4 | 322303221022210121 |
5 | 2013304211030001 |
6 | 45001355214105 |
7 | 4363516340354 |
oct | 726351124431 |
9 | 200876485315 |
10 | 63143455001 |
11 | 2486291a360 |
12 | 102a2747335 |
13 | 5c53a8b533 |
14 | 30b015d29b |
15 | 19986d1cbb |
hex | eb3a4a919 |
63143455001 has 4 divisors (see below), whose sum is σ = 68883769104. Its totient is φ = 57403140900.
The previous prime is 63143454991. The next prime is 63143455013. The reversal of 63143455001 is 10055434136.
63143455001 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 63143455001 - 230 = 62069713177 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (63143455901) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2870157035 + ... + 2870157056.
It is an arithmetic number, because the mean of its divisors is an integer number (17220942276).
Almost surely, 263143455001 is an apocalyptic number.
It is an amenable number.
63143455001 is a deficient number, since it is larger than the sum of its proper divisors (5740314103).
63143455001 is a wasteful number, since it uses less digits than its factorization.
63143455001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5740314102.
The product of its (nonzero) digits is 21600, while the sum is 32.
Adding to 63143455001 its reverse (10055434136), we get a palindrome (73198889137).
The spelling of 63143455001 in words is "sixty-three billion, one hundred forty-three million, four hundred fifty-five thousand, one".
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