Base | Representation |
---|---|
bin | 111010111010111100… |
… | …111100100101101101 |
3 | 20001022010021220210010 |
4 | 322322330330211231 |
5 | 2014032104044013 |
6 | 45021455403433 |
7 | 4366535550063 |
oct | 727274744555 |
9 | 201263256703 |
10 | 63266081133 |
11 | 24916065172 |
12 | 10317823579 |
13 | 5c732c4888 |
14 | 30c2560033 |
15 | 19a43557c3 |
hex | ebaf3c96d |
63266081133 has 4 divisors (see below), whose sum is σ = 84354774848. Its totient is φ = 42177387420.
The previous prime is 63266081107. The next prime is 63266081141. The reversal of 63266081133 is 33118066236.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 63266081133 - 25 = 63266081101 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 63266081091 and 63266081100.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (63266081183) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10544346853 + ... + 10544346858.
It is an arithmetic number, because the mean of its divisors is an integer number (21088693712).
Almost surely, 263266081133 is an apocalyptic number.
It is an amenable number.
63266081133 is a deficient number, since it is larger than the sum of its proper divisors (21088693715).
63266081133 is a wasteful number, since it uses less digits than its factorization.
63266081133 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 21088693714.
The product of its (nonzero) digits is 93312, while the sum is 39.
The spelling of 63266081133 in words is "sixty-three billion, two hundred sixty-six million, eighty-one thousand, one hundred thirty-three".
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