Base | Representation |
---|---|
bin | 101110000100001010011… |
… | …0111111110101100011111 |
3 | 211102020202110211201101120 |
4 | 1130020110313332230133 |
5 | 1312212124243411333 |
6 | 21244252031142023 |
7 | 1222260232121034 |
oct | 134102467765437 |
9 | 24366673751346 |
10 | 6331132013343 |
11 | 2021021a730a5 |
12 | 863023374913 |
13 | 36c03bc32977 |
14 | 17c5dd84d38b |
15 | aea4982bdb3 |
hex | 5c214dfeb1f |
6331132013343 has 4 divisors (see below), whose sum is σ = 8441509351128. Its totient is φ = 4220754675560.
The previous prime is 6331132013309. The next prime is 6331132013411. The reversal of 6331132013343 is 3433102311336.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-6331132013343 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (6331132013243) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1055188668888 + ... + 1055188668893.
It is an arithmetic number, because the mean of its divisors is an integer number (2110377337782).
Almost surely, 26331132013343 is an apocalyptic number.
6331132013343 is a deficient number, since it is larger than the sum of its proper divisors (2110377337785).
6331132013343 is a wasteful number, since it uses less digits than its factorization.
6331132013343 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2110377337784.
The product of its (nonzero) digits is 34992, while the sum is 33.
Adding to 6331132013343 its reverse (3433102311336), we get a palindrome (9764234324679).
The spelling of 6331132013343 in words is "six trillion, three hundred thirty-one billion, one hundred thirty-two million, thirteen thousand, three hundred forty-three".
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