Base | Representation |
---|---|
bin | 1001000000000000010010000… |
… | …0101101010000011100111101 |
3 | 10002001102010202111220020102120 |
4 | 2100000010200231100130331 |
5 | 1131002333103033113203 |
6 | 10122544452432113153 |
7 | 250254054515616651 |
oct | 22000044055203475 |
9 | 3061363674806376 |
10 | 633323541301053 |
11 | 173884007398979 |
12 | 5b0464186957b9 |
13 | 212501cc84c6b5 |
14 | b257046da8a61 |
15 | 4d342ea97eb53 |
hex | 2400120b5073d |
633323541301053 has 4 divisors (see below), whose sum is σ = 844431388401408. Its totient is φ = 422215694200700.
The previous prime is 633323541301037. The next prime is 633323541301097. The reversal of 633323541301053 is 350103145323336.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 633323541301053 - 24 = 633323541301037 is a prime.
It is a super-2 number, since 2×6333235413010532 (a number of 30 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 633323541300996 and 633323541301014.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (633323541801053) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 105553923550173 + ... + 105553923550178.
It is an arithmetic number, because the mean of its divisors is an integer number (211107847100352).
Almost surely, 2633323541301053 is an apocalyptic number.
It is an amenable number.
633323541301053 is a deficient number, since it is larger than the sum of its proper divisors (211107847100355).
633323541301053 is a wasteful number, since it uses less digits than its factorization.
633323541301053 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 211107847100354.
The product of its (nonzero) digits is 874800, while the sum is 42.
Adding to 633323541301053 its reverse (350103145323336), we get a palindrome (983426686624389).
The spelling of 633323541301053 in words is "six hundred thirty-three trillion, three hundred twenty-three billion, five hundred forty-one million, three hundred one thousand, fifty-three".
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