Base | Representation |
---|---|
bin | 101110001110010101100… |
… | …1001010100110111100001 |
3 | 211111100011010121121221001 |
4 | 1130130223021110313201 |
5 | 1313041401001331331 |
6 | 21302304032032001 |
7 | 1223662531136530 |
oct | 134345311246741 |
9 | 24440133547831 |
10 | 6352980495841 |
11 | 202a313960401 |
12 | 867300392601 |
13 | 371111574115 |
14 | 17d6b342c317 |
15 | b03c79cb561 |
hex | 5c72b254de1 |
6352980495841 has 8 divisors (see below), whose sum is σ = 7437635702784. Its totient is φ = 5312596930080.
The previous prime is 6352980495781. The next prime is 6352980495853. The reversal of 6352980495841 is 1485940892536.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 6352980495841 - 215 = 6352980463073 is a prime.
It is a super-3 number, since 3×63529804958413 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not an unprimeable number, because it can be changed into a prime (6352980495881) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 11067909985 + ... + 11067910558.
It is an arithmetic number, because the mean of its divisors is an integer number (929704462848).
Almost surely, 26352980495841 is an apocalyptic number.
It is an amenable number.
6352980495841 is a deficient number, since it is larger than the sum of its proper divisors (1084655206943).
6352980495841 is a wasteful number, since it uses less digits than its factorization.
6352980495841 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 22135820591.
The product of its (nonzero) digits is 74649600, while the sum is 64.
The spelling of 6352980495841 in words is "six trillion, three hundred fifty-two billion, nine hundred eighty million, four hundred ninety-five thousand, eight hundred forty-one".
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