641113276703 has 4 divisors (see below), whose sum is σ = 674856080760. Its totient is φ = 607370472648.

The previous prime is 641113276697. The next prime is 641113276721. The reversal of 641113276703 is 307672311146.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-641113276703 is a prime.

It is a super-2 number, since 2×641113276703² (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (641113276103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16871402000 + ... + 16871402037.

It is an arithmetic number, because the mean of its divisors is an integer number (168714020190).

Almost surely, 2^641113276703 is an apocalyptic number.

641113276703 is a deficient number, since it is larger than the sum of its proper divisors (33742804057).

641113276703 is a wasteful number, since it uses less digits than its factorization.

641113276703 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 33742804056.

The product of its (nonzero) digits is 127008, while the sum is 41.

Adding to 641113276703 its reverse (307672311146), we get a palindrome (948785587849).

The spelling of 641113276703 in words is "six hundred forty-one billion, one hundred thirteen million, two hundred seventy-six thousand, seven hundred three".