Base | Representation |
---|---|
bin | 11101001001111101010101… |
… | …11101010001110001100111 |
3 | 22102000020001002120022222112 |
4 | 32210332222331101301213 |
5 | 31400420123311031303 |
6 | 344205254354151235 |
7 | 16335033563555255 |
oct | 1644765275216147 |
9 | 272006032508875 |
10 | 64113845017703 |
11 | 19479590082568 |
12 | 7235838b8251b |
13 | 29a0ba9640910 |
14 | 11b91ab7895d5 |
15 | 762b354b50d8 |
hex | 3a4faaf51c67 |
64113845017703 has 16 divisors (see below), whose sum is σ = 69057862263936. Its totient is φ = 59171569428960.
The previous prime is 64113845017679. The next prime is 64113845017721. The reversal of 64113845017703 is 30771054831146.
It is a cyclic number.
It is not a de Polignac number, because 64113845017703 - 232 = 64109550050407 is a prime.
It is a super-2 number, since 2×641138450177032 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (64113845017723) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3553382600 + ... + 3553400642.
It is an arithmetic number, because the mean of its divisors is an integer number (4316116391496).
Almost surely, 264113845017703 is an apocalyptic number.
64113845017703 is a deficient number, since it is larger than the sum of its proper divisors (4944017246233).
64113845017703 is a wasteful number, since it uses less digits than its factorization.
64113845017703 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 51134.
The product of its (nonzero) digits is 1693440, while the sum is 50.
Adding to 64113845017703 its reverse (30771054831146), we get a palindrome (94884899848849).
The spelling of 64113845017703 in words is "sixty-four trillion, one hundred thirteen billion, eight hundred forty-five million, seventeen thousand, seven hundred three".
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