Base | Representation |
---|---|
bin | 11101001010001100000100… |
… | …11110001011101010010010 |
3 | 22102000222110101221020200121 |
4 | 32211012002132023222102 |
5 | 31401032323430242041 |
6 | 344213043343540454 |
7 | 16335433611424336 |
oct | 1645060236135222 |
9 | 272028411836617 |
10 | 64121755712146 |
11 | 1948197a4a3370 |
12 | 72372862ba72a |
13 | 29a186a515bc2 |
14 | 11b971c2477c6 |
15 | 762e49c1e7d1 |
hex | 3a518278ba92 |
64121755712146 has 16 divisors (see below), whose sum is σ = 104930436758688. Its totient is φ = 29145161648800.
The previous prime is 64121755711999. The next prime is 64121755712213.
64121755712146 is nontrivially palindromic in base 10.
It is a super-3 number, since 3×641217557121463 (a number of 42 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 64121755712093 and 64121755712102.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 53946115 + ... + 55121926.
It is an arithmetic number, because the mean of its divisors is an integer number (6558152297418).
Almost surely, 264121755712146 is an apocalyptic number.
64121755712146 is a deficient number, since it is larger than the sum of its proper divisors (40808681046542).
64121755712146 is a wasteful number, since it uses less digits than its factorization.
64121755712146 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 109094777.
The product of its digits is 2822400, while the sum is 52.
The spelling of 64121755712146 in words is "sixty-four trillion, one hundred twenty-one billion, seven hundred fifty-five million, seven hundred twelve thousand, one hundred forty-six".
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