Base | Representation |
---|---|
bin | 101110101001111110111… |
… | …0101011001110111101011 |
3 | 211201000101200111211200221 |
4 | 1131103331311121313223 |
5 | 1320024443024402000 |
6 | 21345443131110511 |
7 | 1231164002221156 |
oct | 135237565316753 |
9 | 24630350454627 |
10 | 6412349840875 |
11 | 205250a352010 |
12 | 87690aba2437 |
13 | 3768b3461594 |
14 | 182506238c9d |
15 | b1beeba861a |
hex | 5d4fdd59deb |
6412349840875 has 16 divisors (see below), whose sum is σ = 8730122839776. Its totient is φ = 4663527156000.
The previous prime is 6412349840863. The next prime is 6412349840957. The reversal of 6412349840875 is 5780489432146.
It is not a de Polignac number, because 6412349840875 - 25 = 6412349840843 is a prime.
It is a super-2 number, since 2×64123498408752 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2331762204 + ... + 2331764953.
It is an arithmetic number, because the mean of its divisors is an integer number (545632677486).
It is a 1-persistent number, because it is pandigital, but 2⋅6412349840875 = 12824699681750 is not.
Almost surely, 26412349840875 is an apocalyptic number.
6412349840875 is a deficient number, since it is larger than the sum of its proper divisors (2317772998901).
6412349840875 is a wasteful number, since it uses less digits than its factorization.
6412349840875 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4663527183 (or 4663527173 counting only the distinct ones).
The product of its (nonzero) digits is 46448640, while the sum is 61.
The spelling of 6412349840875 in words is "six trillion, four hundred twelve billion, three hundred forty-nine million, eight hundred forty thousand, eight hundred seventy-five".
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