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6412500242447 = 13493269249419
BaseRepresentation
bin101110101010000011011…
…0011001001000000001111
3211201000210011112000212112
41131110012303021000033
51320030300030224242
621345510102454235
71231200506502545
oct135240663110017
924630704460775
106412500242447
112052587238a32
1287695143437b
133769086711b0
1418251c1c9d95
15b1c0ceb6c82
hex5d506cc900f

6412500242447 has 4 divisors (see below), whose sum is σ = 6905769491880. Its totient is φ = 5919230993016.

The previous prime is 6412500242419. The next prime is 6412500242483. The reversal of 6412500242447 is 7442420052146.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 6412500242447 - 218 = 6412499980303 is a prime.

It is a super-2 number, since 2×64125002424472 (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3412500242447) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 246634624697 + ... + 246634624722.

It is an arithmetic number, because the mean of its divisors is an integer number (1726442372970).

Almost surely, 26412500242447 is an apocalyptic number.

6412500242447 is a deficient number, since it is larger than the sum of its proper divisors (493269249433).

6412500242447 is a wasteful number, since it uses less digits than its factorization.

6412500242447 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 493269249432.

The product of its (nonzero) digits is 430080, while the sum is 41.

The spelling of 6412500242447 in words is "six trillion, four hundred twelve billion, five hundred million, two hundred forty-two thousand, four hundred forty-seven".

Divisors: 1 13 493269249419 6412500242447