6412513136339 has 16 divisors (see below), whose sum is σ = 6739743343872. Its totient is φ = 6093416675808.

The previous prime is 6412513136321. The next prime is 6412513136369. The reversal of 6412513136339 is 9336313152146.

It is not a de Polignac number, because 6412513136339 - 2⁸ = 6412513136083 is a prime.

It is a super-3 number, since 3×6412513136339³ (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 6412513136293 and 6412513136302.

It is not an unprimeable number, because it can be changed into a prime (6412513136369) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 14164562 + ... + 14610264.

It is an arithmetic number, because the mean of its divisors is an integer number (421233958992).

Almost surely, 2^{6412513136339} is an apocalyptic number.

6412513136339 is a deficient number, since it is larger than the sum of its proper divisors (327230207533).

6412513136339 is a wasteful number, since it uses less digits than its factorization.

6412513136339 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 454826.

The product of its digits is 1049760, while the sum is 47.

The spelling of 6412513136339 in words is "six trillion, four hundred twelve billion, five hundred thirteen million, one hundred thirty-six thousand, three hundred thirty-nine".