Base | Representation |
---|---|
bin | 1001000111010001010011010… |
… | …1110110110110111011011001 |
3 | 10010002200212202020120100221010 |
4 | 2101310110311312312323121 |
5 | 1133024231033014410131 |
6 | 10151542524515404133 |
7 | 252040205320351650 |
oct | 22164246566667331 |
9 | 3102625666510833 |
10 | 641312535310041 |
11 | 176384134221171 |
12 | 5bb167ba5b3649 |
13 | 216ac6881cc32a |
14 | b451999a58197 |
15 | 4e22026570b46 |
hex | 2474535db6ed9 |
641312535310041 has 32 divisors (see below), whose sum is σ = 978624894954240. Its totient is φ = 365944622109696.
The previous prime is 641312535310019. The next prime is 641312535310079. The reversal of 641312535310041 is 140013535213146.
It is not a de Polignac number, because 641312535310041 - 217 = 641312535178969 is a prime.
It is a super-2 number, since 2×6413125353100412 (a number of 30 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (641312535310141) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 37296325 + ... + 51707261.
It is an arithmetic number, because the mean of its divisors is an integer number (30582027967320).
Almost surely, 2641312535310041 is an apocalyptic number.
It is an amenable number.
641312535310041 is a deficient number, since it is larger than the sum of its proper divisors (337312359644199).
641312535310041 is a wasteful number, since it uses less digits than its factorization.
641312535310041 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 14413953.
The product of its (nonzero) digits is 129600, while the sum is 39.
The spelling of 641312535310041 in words is "six hundred forty-one trillion, three hundred twelve billion, five hundred thirty-five million, three hundred ten thousand, forty-one".
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