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6413134313146 = 211226500555013
BaseRepresentation
bin101110101010010110010…
…0101111011011010111010
3211201002102100122011100111
41131110230211323122322
51320033044341010041
621350053033054534
71231222306143301
oct135245445733272
924632370564314
106413134313146
112052882147700
12876aa985744a
133769a9b38862
1418257c4c1438
15b1c489b4981
hex5d52c97b6ba

6413134313146 has 12 divisors (see below), whose sum is σ = 10573721450586. Its totient is φ = 2915061051320.

The previous prime is 6413134313141. The next prime is 6413134313149.

6413134313146 is nontrivially palindromic in base 10.

It can be written as a sum of positive squares in only one way, i.e., 4540585648225 + 1872548664921 = 2130865^2 + 1368411^2 .

It is a super-2 number, since 2×64131343131462 (a number of 26 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 6413134313099 and 6413134313108.

It is not an unprimeable number, because it can be changed into a prime (6413134313141) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 13250277265 + ... + 13250277748.

Almost surely, 26413134313146 is an apocalyptic number.

6413134313146 is a deficient number, since it is larger than the sum of its proper divisors (4160587137440).

6413134313146 is a wasteful number, since it uses less digits than its factorization.

6413134313146 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 26500555037 (or 26500555026 counting only the distinct ones).

The product of its digits is 186624, while the sum is 40.

The spelling of 6413134313146 in words is "six trillion, four hundred thirteen billion, one hundred thirty-four million, three hundred thirteen thousand, one hundred forty-six".

Divisors: 1 2 11 22 121 242 26500555013 53001110026 291506105143 583012210286 3206567156573 6413134313146