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64132814697 = 372436277651
BaseRepresentation
bin111011101110100111…
…010001011101101001
320010112112012112201020
4323232213101131221
52022321000032242
645243500443053
74430161634100
oct735647213551
9203475175636
1064132814697
11252203359a6
1210519b49489
136080a41583
1431656db037
151a054b06ec
hexeee9d1769

64132814697 has 12 divisors (see below), whose sum is σ = 99471304656. Its totient is φ = 36647322600.

The previous prime is 64132814659. The next prime is 64132814717. The reversal of 64132814697 is 79641823146.

It is a happy number.

It is not a de Polignac number, because 64132814697 - 210 = 64132813673 is a prime.

It is a super-2 number, since 2×641328146972 (a number of 22 digits) contains 22 as substring.

It is a hoax number, since the sum of its digits (51) coincides with the sum of the digits of its distinct prime factors.

It is not an unprimeable number, because it can be changed into a prime (64132814197) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 218138679 + ... + 218138972.

It is an arithmetic number, because the mean of its divisors is an integer number (8289275388).

Almost surely, 264132814697 is an apocalyptic number.

It is an amenable number.

64132814697 is a deficient number, since it is larger than the sum of its proper divisors (35338489959).

64132814697 is a wasteful number, since it uses less digits than its factorization.

64132814697 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 436277668 (or 436277661 counting only the distinct ones).

The product of its digits is 1741824, while the sum is 51.

The spelling of 64132814697 in words is "sixty-four billion, one hundred thirty-two million, eight hundred fourteen thousand, six hundred ninety-seven".

Divisors: 1 3 7 21 49 147 436277651 1308832953 3053943557 9161830671 21377604899 64132814697